Testing and measuring materials for testing knowledge in computer science and ICT; Grade 10
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Testing and measuring materials for testing knowledge in computer science and ICT; Grade 10
Codifier of content elements and level requirements
preparing 10th grade students of general education institutions for final testing in computer science and ICT
The codifier is compiled on the basis of the Federal component of state standards for basic general and secondary (complete) general education in computer science and ICT (basic level) (Order of the Ministry of Education of Russia dated March 5, 2004 No. 1089).
List of content elements checked when monitoring the quality of students’ training:
Topics for section No. 1 “Information technology”
:
- Coding of text information.
- Coding and processing of graphic information.
- Coding of audio information.
- Coding and processing of numerical information.
- Spreadsheets.
Topics for section No. 2 “Communication technologies
:
- Local computer networks.
- Global computer network Internet.
- Email.
List of requirements for the level of training of students:
know/understand
- concepts: information, computer science;
- units of measurement of the amount of information, the speed of information transfer and the relationship between them;
- essence of the alphabetical approach to information measurement
- purpose and functions of information and communication technologies used;
- presentation of numerical, text, graphic, audio information on a computer;
- concepts: computer network, global network, email,
be able to
- solve problems of measuring information contained in a text from the perspective of the alphabetical approach, calculate the amount of information transmitted through communication channels at a known transmission speed;
- recalculate the amount of information and the speed of information transmission into different units;
- represent numerical information in the binary number system, perform arithmetic operations on numbers in the binary number system;
- represent and process numerical information in spreadsheets.
Specification of test materials
for the final test
in computer science and ICT. Grade 10
This test is intended to test the quality of knowledge in Computer Science and ICT for 10th grade students.
The test was compiled on the basis of the author’s program N.D. Ugrinovich (Profile course at a basic level).
The total number of tasks in the test is 14.
The test consists of two parts.
Part 1 contains 10 tasks with a choice of one correct answer. Most tasks are designed to take a short time (3 minutes).
Part 2 contains 4 tasks. This part contains short-answer tasks that require you to independently formulate and write the answer in the form of a number or a sequence of characters.
For the correct answer to each task in Part 1, the student receives 1 point, the maximum number is 10 points.
For correctly completed task of Part 2, the student receives 2 points, the maximum number is 8 points.
The maximum number of points for the entire work is 18.
Completion time: 45 minutes.
Scale for converting the primary score into a mark on a five-point scale:
points | 15 -18 | 10 -14 | 5 — 9 | 0 — 4 |
grade | 5 | 4 | 3 | 2 |
Option #1.
Part 1. Multiple Choice Questions
A1. Assuming that each character is encoded in Unicode, estimate the information volume of the following phrase: I love a thunderstorm in early May
.
- 192 bit
- 20 bytes
- 50 bytes
- 284 bit
A2. The text (characters are encoded in KOI-8 encoding) takes up 0.25 KB of computer memory. How many characters does this text contain?
- 64
- 128
- 256
- 512
A3. The number of colors that can be reproduced on a monitor screen is:
- color depth
- resolution
- graphic mode
- palette
A4. In the process of converting a raster graphic image, the number of colors decreased from 256 to 16. Its information volume decreased by:
- 2 times
- 4 times
- 8 times
- 16 times
Test No. 1 in computer science and ICT with answers, grade 10
Lesson plan in computer science and ICT on the topic “Test No. 1” based on the textbook by I. G. Semakina Informatics, grade 10
Purpose: testing students’ knowledge, skills and abilities on the topic. Lesson type: lesson on monitoring knowledge, skills and abilities.
Lesson progress
1. Organizational moment : Greeting, checking those present. 2. Test on the topic: “Information” 10th grade Test No. 1. Semakin Option 1 1. If by information we mean only what is distributed through books, manuscripts, works of art, the media, then to what philosophical concept can it be applied? will it be attributed? a) to attributive; b) to functional; c) to anthropocentric. 2. Data are: a) individual facts characterizing objects, processes, phenomena; b) identified patterns in a certain subject area; c) a set of information necessary for organizing the activities of the enterprise; d) registered signals. 3. What is a graphical form of representing mathematical information: a) mathematical equation; c) table of function values; b) function graph; d) mathematical expression. 4. In one of the Unicode encodings, each character is encoded with 16 bits. Determine the size of the following sentence in this encoding: The forest drops its crimson attire, the frost turns the withered field silver. 5. A group of schoolchildren came to the pool, which had 4 swimming lanes. The coach said that the group would swim in lane No. 3. How much information did the students receive from this message? 6. The message that your friend lives on the 10th floor carries 4 bits of information. How many floors are there in the house? 7. Convert to bits: 57 KB, 57 MB, 57 GB. 8. The alphabet of some sign system consists of 128 characters (N). How much information will a 56-character sentence (Ic) contain? Write the answer in bytes. 9. What is the sampling frequency of the analog signal (in Hz), if the information volume of a stereo audio file with a sound duration of 4 seconds and an audio coding depth of 16 bits is equal to 678.5 KB? a) 5428; b) 43424; c) 86848; d) 173696. 10.(2 points) The color scanner has a resolution of 512*1024 dpi. The amount of memory occupied by a scanned image measuring 2*4 inches is 12 MB. What is the scanner's color depth expressed in bits? Grade 10 Test No. 1. Semakin Option 2 1. According to the functional concept, information and information processes are inherent ... a) only in living nature; b) only to humans; c) all material objects of the world. 2. Cybernetics is: a) the science of artificial intelligence; b) the science of the laws of control processes and information transfer in machines, living organisms and society; c) computer science; d) the science of the forms and laws of human thinking. 3. What is the symbolic form of representing mathematical information? a) mathematical equation; b) graph of the function; c) diagram; d) verbal formulation of the problem. 4. In one of the Unicode encodings, each character is encoded with 16 bits. Determine the size of the following sentence in this encoding: I loved you: love, perhaps, has not completely died out in my soul. 5. A telegram was received: “Meet car No. 7.” It is known that the train has 16 cars. How much information was received? 6. The message that Petya lives in the second entrance carries 3 bits of information. How many entrances are there in the house? 7. Convert to bits: 51 KB, 51 MB, 51 GB. 8. The alphabet of some sign system consists of 256 characters (N). How much information will a 40-character sentence (Ic) contain? Write the answer in bytes. 9. How much disk space in kilobytes will be needed to store two-channel 16-bit audio with a sampling rate of 24 kHz for 512 seconds? a) 24000; b) 6000; c) 24; d) 2400. 10. (2 points) The color scanner has a resolution of 512*1024 dpi2. The amount of memory occupied by a scanned image measuring 2*4 inches is about 8 MB. What is the scanner's color depth expressed in bits? Answers: Option1
1.c 2.d(a) 3.b 4.120 bytes 5.2 bits 6.16 floors 7.57*213 bits 466944 57*223 bits 478150656 57*233 bits 489626271744 8. i=7 bits Ic=392 bits=49 bytes 9 .b 10.24 In inches 1024x512=2^19 pixels.
The image will take 2*4=8 inches = 8*2^19 pixels. 12 MB = 12*2^10 kbytes = 12*2^20 bytes = 12*2^23 bits. Divide ( 12*2^23 ) / (8 * 2^19 ) = 3*2^3 = 24 bits Answers: Option 2
1.a 2.b 3.a 4.132 bytes 5. 4 bits 6. 8 entrances 7. 51*213 bits 417792 51*223 bits 427819008 51*233 bits 438086664192 8. i=8 bits Ic=320 bits=40 bytes 9.a 10.16 In inches 1024x512=2^19 dots.
The image will take 2*4=8 inches = 8*2^19 pixels. 8 MB = 8*2^10 kbytes = 8*2^20 bytes = 8*2^23 bits. Divide ( 8 * 2^23 ) / (8 * 2^19 ) = 2^4 = 16 bits, Assessment 10 - 11 = 5 8 - 9 = 4 6 - 7 = 3 3. Lesson summary Download Test No.
1 on computer science and ICT. Information. Grade 10
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Examples and assignments for the topic “Information and information processes”
Test in computer science for grade 10 on the topic “Fundamentals of Logic”
Test No. 3 ___________________10A___
on the topic “Information and information processes.” (Fundamentals of Logic)
Option 1.
- Construct a truth table for a given logical expression:
A)
B)
The symbol F denotes one of the following logical expressions from two arguments: A and B. Given the truth table of the expression F. Which expression corresponds to F?
A ) A → (¬ A ∨ ¬ B )
B )
A ∧ B
C )
¬ A → B
D )
¬ A ∧ ¬ B
- It is known that for the numbers A, B, C the statement is true
What is C equal if A=45, B=18
- For which of the indicated values of the number X is the statement true?
((X < 5)→(X < 3))
((X < 2)→(X < 1))
A)1 B)2 C)3 d)4
- For which value of the number Z is the statement ((Z > 2)
(Z > 4)) →(Z > 3)
will be false?
1) 1 2) 2 3) 3 4) 4
- Below are the queries and the number of pages that the search engine found for these queries in a certain segment of the Internet:
cruiser | battleship 7000 cruiser 4800 battleship 4500
How many pages will be found for the query cruiser & battleship
- Below are the queries and the number of pages that the search engine found for these queries in a certain segment of the Internet:
March & May & June 150 March & May 420 March & (May | June) 520
How many pages will be found for the query March & June
- Simplify logical expressions:
A)
B)
IN)
- Solve Logic Equation(¬K
M) → (¬L
M
N) =0 .
Write your answer as a string of four characters: the values of the variables K, L, M and N (in that order). So, for example, line 1101 corresponds to the fact that K=1, L=1, M=0, N=1.
Test No. 3 ___________________10A___
on the topic “Information and information processes.” (Fundamentals of Logic)
Option 2.
- Construct a truth table for a given logical expression:
A)
B)
The symbol F denotes one of the following logical expressions from three arguments: X, Y and Z. Given a fragment of the truth table of the expression F. Which expression corresponds to F? X ∧ Y) ∧ Z
B) ¬(X ∨ ¬Y) ∨ Z
B) ¬(X ∧ Y) ∨ Z
D) (X ∨ Y) ∧ Z
- It is known that for the numbers A, B, C the statement is true
What is C equal if A=25, B=48
- For what number X is the statement true ((X > 3) (X < 3)) →(X < 1)
1) 1 2) 2 3) 3 4) 4
- For which value of the number Y is the statement (Y < 5)
((Y > 1) → (Y > 5))
will be true?
1) 1 2) 2 3) 3 4) 4
- Below are the queries and the number of pages that the search engine found for these queries in a certain segment of the Internet:
cakes | pies 12000 cakes & pies 6500 pies 7700
How many pages will be found for the query cakes?
- Below are the queries and the number of pages that the search engine found for these queries in a certain segment of the Internet:
cornflowers & lilies of the valley 650 lilies of the valley & buttercups 230 lilies of the valley & (cornflowers | buttercups) 740
How many pages will be found for the query lilies of the valley & cornflowers & buttercups
- Simplify logical expressions:
A)
B)
IN)
- Solve Logic Equation
Write your answer as a string of four characters: the values of variables A, B, C and D (in that order). So, for example, line 1101 corresponds to the fact that A=1, B=1, C=0, D=1.